Answer:
b) 63.7 kJ
Explanation:
[tex]2 CO_{(g)} + C _{(s)} ----> C_{3}O_{2}[/tex]
we have ΔH = 127.3 kJ/mol
for 1.00 mole of CO the equation can be re-written as,
[tex]CO_{(g)} +\frac{1}{2} C _{(s)} ---->\frac{1}{2} C_{3}O_{2}[/tex]
since the number of moles are halved ΔH also gets halved as per Hesse's law of constant summation,
ΔH = [tex]\frac{127.3}{2}[/tex]
= 63.7 kJ
