A nail is partially inserted into a block of wood, with a length of 0.0300 m protruding above the top of the block. To hammer the nail in the rest of the way, you drop a 20.0 kg metal cylinder onto it. The cylinder rides on vertical tracks that exert an upward friction force of 16.0 N on the cylinder as it falls. You release the cylinder from rest at a height of 1.50 m above the top of the nail. The cylinder comes to rest on top of the block of wood, with the nail fully inside the block. Use the work-energy theorem to find the speed of the cylinder just as it hits the nail.

Respuesta :

Answer:

v = 5.19 m/s

Explanation:

Using the work-energy theorem:

W = Δk

where W is the work and Δk is the change in the kinetic energy

Now the work of all the system is equal to:

[tex]W = Mgd - F_kd[/tex]

where M is the mass, g the gravity, d the distance and [tex]F_k[/tex] the friction force, it means that Mgd is the work of the gravitational force and [tex]F_kd[/tex] is the work of the friction force

Also, the kinetic energy could be calulate by:

K = [tex]\frac{1}{2}MV^2[/tex]

where M is the mass and V the velocity.

Replacing:

[tex]Mgd - F_kd = \frac{1}{2}MV^2[/tex]

[tex](20)(9.8)(1.5) - (16)(1.5) = \frac{1}{2}(20)V^2[/tex]

Solving for V, we get:

v = 5.19 m/s

 

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