Answer:
0.077 M
Explanation:
Data Given :
The concentration of half normal (NaCl) saline = 0.45g / 100 g
So,
Volume of Solution = 100 g = 100 mL
Volume of Solution in Liter = 100 mL / 1000
Volume of Solution = 0.1 L
molar mass of NaCl = 58.44 g/mol
Molarity:
Molarity is the representation of the solution. It is amount of solute in moles per liter of solution and represented by M
Formula used for Molarity
M = moles of solute / Liter of solution . . . . . . . . . . (1)
Now to find number of moles of Nacl
no. of moles of NaCl = mass of NaCl / molar mass
no. of moles of NaCl = 0.45g / 58.44 g/mol
no. of moles of NaCl = 0.0077 g
Put values in the eq (1)
M = moles of solute / Liter of solution . . . . . . . . . . (1)
M = 0.0077 g / 0.1 L
M = 0.077 M
So the molarity of half-normal saline solution (0.45% NaCl) = 0.077 M
The molarity of half-normal saline solution (0.45% NaCl) is gotten to be; 0.077 M.
We are given;
The concentration of half normal saline solution(NaCl) = 0.45% = 0.45g/100g
From conversion, we know that 100 g = 100 mL
Thus converting to liters;
Volume of Solution = 100/1000 L
Volume of Solution = 0.1 L
Now,
The molar mass of NaCl = 58.44 g/mol
Th Formula to calculate Molarity is given as;
M = Number of moles of solute/Volume of solution
We don't have number of moles here.
Thus, since concentration is 0.45g/100g, and molar mass of NaCl = 58.44 g/mol, then;
Number of moles of NaCl = 0.45g/58.44 g/mol
Number of moles of NaCl = 0.0077 mol
Thus, Molarity is;
M = 0.0077mol/0.1 L
M = 0.077 M
In conclusion, the molarity of half-normal saline solution (0.45% NaCl) is gotten to be 0.077 M.
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