Answer:
it will take 5.5 seconds to hit the ground
Step-by-step explanation:
A projectile is shot vertically from the ground level. It’s height h, in feet, after t seconds is given by [tex]h = 88t - 16t ^2[/tex]
When the projectile hits the ground then the height becomes 0
[tex]h = 88t - 16t ^2[/tex]
[tex]0 = 88t - 16t ^2[/tex]
GCF is -8t
[tex]0 = 8t(11 - 2t)[/tex]
now set each factor =0 and solve for t
[tex]8t=0, t=0[/tex]
[tex]11-2t=0, t=\frac{11}{2}[/tex]
So it will take 5.5 seconds to hit the ground
Answer:
5.5 seconds.
Step-by-step explanation:
The given function is
[tex]h = 88t - 16t ^2[/tex]
where, h is height (in feet) of projectile after t seconds.
We need to find the time taken by projectile to hit the ground.
At ground level, the height of projectile is 0.
Substitute h=0 in the given function to find the time at which it hit the ground.
[tex]0=88t - 16t ^2[/tex]
[tex]0=8t(11 - 2t)[/tex]
Using zero product property we get
[tex]8t=0\Rightarrow t=0[/tex]
[tex]11-2t=0\Rightarrow t=\frac{11}{2}=5.5[/tex]
It mean projectile hits the ground at x=0 and x=5.5 seconds. We know that x=0 is the initial stage.
Therefore, so time taken by projectile to hit the ground is 5.5 seconds.
