Answer:
720 Arrangements
Step-by-step explanation:
Given the numbers could be from 0 - 9 and none of them is to be repeated.
The first place could be filled in 10 ways. (0 - 9)
The second place could be filled in 9 ways. (Excluding the one in the first place).
The third place could be filled in 8 ways. (Excluding the two numbers in the first two places).
Therefore, the total number of arrangements possible for the lock is: [tex]$ 10 \times 9 \times 8 $[/tex] = 720 ways.
