Answer:
Decision rule for rejecting is
reject H0 is test statistic <-1.233
Step-by-step explanation:
Given that a  sample of 1300 computer chips revealed that 27% of the chips do not fail in the first 1000 hours of their use, as against company literature of 29%
To test this we create hypotheses as
[tex]H_0: p = 29%\\H_a: p <27%[/tex]
(left tailed test at 10% significance level)
p difference = -0.02
STd error of p = [tex]\sqrt{0.29*0.71/1300} \\=0.0126[/tex]
Test statistic = p diff/std error = -0.1587
For 10% significance level for right tailed test we can reject H0 if
test statistic <-1.645
Decision rule for rejecting is
reject H0 is test statistic <-1.233
