Respuesta :
Answer:
Step-by-step explanation:
Let us take side of first square be a
and other square side be L
It is given area of first square is equal to length of other
i.e. [tex]a^2=L[/tex]
also
Sum of area of two square is 65
[tex]L^2+a^2=65[/tex]
i.e.
[tex]a^4+a^2=65----1[/tex]
also Difference of area of two square is
[tex]L^2-a^2=33[/tex]
[tex]a^2-a^2=33-----2[/tex]
adding 1 and 2 we get
[tex]2a^4=98[/tex]
[tex]a^4=49[/tex]
[tex]a^2=7[/tex]
i.e. [tex]L=7[/tex]
and [tex]a=\sqrt{7}[/tex]
Perimeter of first Square
[tex]P_1=4a=4\sqrt{7}[/tex]
[tex]P_2=4 L=4\times 7[/tex]
Sum of Perimeter
[tex]=4(\sqrt{7}+7) units[/tex]
Answer:
44
Step-by-step explanation:
Let the side length of the larger square be x and the side length of the smaller square be y. We are told x^2 + y^2 = 65 and x^2 - y^2 = 33. Adding these two equations gives 2x^2 = 98, so x^2 = 49. Since x must be positive, we have x=7. Substituting this into either equation above gives us y^2 = 16. Since y must be positive, we have y=4. The perimeter of the larger square is 4x and that of the smaller square is 4y, so the sum of their perimeters is 4x+4y = 4(x+y) = \boxed{44}
