The force required to slow the truck was -5020 N
Explanation:
First of all, we find the acceleration of the truck, which is given by
[tex]a=\frac{v-u}{t}[/tex]
where
v is the final velocity
u is the initial velocity
t is the time
For the truck in this problem,
v = 11.5 m/s
u = 21.9 m/s
t = 2.88 s
So the acceleration is
[tex]a=\frac{11.5-21.9}{2.88}=-3.6 m/s^2[/tex]
where the negative sign means that this is a deceleration.
Now we can find the force exerted on the truck, which is given by Newton's second law:
[tex]F=ma[/tex]
where
m = 1390 kg is the mass of the truck
[tex]a=-3.6 m/s^2[/tex] is the acceleration
And substituting,
[tex]F=(1390)(-3.6)=-5004 N[/tex]
So the closest answer among the option is -5020 N.
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