Answer:
x = -11, y = -7
Step-by-step explanation:
[tex]\left\{\begin{array}{ccc}2x-4y=6&\text{multiply both sides by 3}\\-3x+3y=12&\text{multiply both sides by 4}\end{array}\right\\\\\underline{+\left\{\begin{array}{ccc}6x-12y=18\\-12x+12y=48\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad-6x=66\qquad\text{divide both sides by (-6)}\\.\qquad\dfrac{-6x}{-6}=\dfrac{66}{-6}\\.\qquad \boxed{x=-11}[/tex]
[tex]\text{Put it to (2):}\\\\-3(-11)+3y=12\\33+3y=12\qquad\text{subtract 33 from both sides}\\3y=-21\qquad\text{divide both sides by 3}\\\dfrac{3y}{3}=\dfrac{-21}{3}\\y=-7[/tex]
