Answer:
[tex]\frac{7}{12}[/tex]
Step-by-step explanation:
We are given that
The probability of pulling a red marble=[tex]\frac{1}{4}[/tex]
The probability of pulling a blue marble=[tex]\frac{1}{3}[/tex]
We have to find the probability that a marble at randomly pulled from the urn will be one of those two colors ( red or blue)
When a marble is of red color then it can not be of blue color .
When a marble is of blue color then it can not be of red color.
[tex]P(Red\cap blue)=0[/tex]
We know that
[tex]P(A\cup B)=P(A)+P(B)-P(A\cap B)[/tex]
A=Red marble
B=Blue marble
[tex]P(A)=\frac{1}{4}[/tex]
[tex]P(B)=\frac{1}{3}[/tex]
Substitute the values then, we get
[tex]P(Red\cup blue)=\frac{1}{4}+\frac{1}{3}=\frac{3+4}{12}=\frac{7}{12}[/tex]
Hence, the probability of pulling red or blue marble from the urn=[tex]\frac{7}{12}[/tex]
