an ice skater starts with a velocity of 2.25 m/s in a 50.0 direction. after 8.33 m/s in a 120 direction. what is the y-component of her accerleration

Respuesta :

The y-component of the acceleration is [tex]0.28 m/s^2[/tex]

Explanation:

The y-component of the ice skater acceleration can be calculated with the equation

[tex]a_y = \frac{v_y-u_y}{t}[/tex]

where

[tex]v_y[/tex] is the y-component of the final velocity

[tex]u_y[/tex] is the y-component of the initial velocity

t is the time elapsed

Here we have:

  • Initial velocity is [tex]u=2.25 m/s[/tex] at [tex]\theta_1=50.0^{\circ}[/tex], so its y-component is [tex]u_y = u sin \theta_1 = (2.25)(sin 50.0^{\circ})=1.72 m/s[/tex]
  • Final velocity is [tex]v=4.65 m/s[/tex] at [tex]\theta_2=120.0^{\circ}[/tex], so its y-component is [tex]v_y = v sin \theta_2 = (4.65)(sin 120.0^{\circ})=4.03 m/s[/tex]

The time elapsed is

t = 8.33 s

Therefore, the y-component of the acceleration is

[tex]a_y = \frac{4.03-1.72}{8.33}=0.28 m/s^2[/tex]

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Answer:

0.28

Explanation:

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