Answer:
option A
Explanation:
given,
length of the longest pipe = L = 4.88 m
speed of sound = 344 m/s
pipe is open at one end and closed at the other
frequency = ?
frequency of standing wave for the pipe opened at the one end and closed at the other.
[tex]f = n \dfrac{v}{4L}[/tex]
v = velocity of wave
n = nth harmonic n = 1
L is the length of pipe
f is frequency
[tex]f =1 \times \dfrac{344}{4\times 4.88}[/tex]
[tex]f =17.63\ Hz[/tex]
Hence, the correct answer is option A
