Answer:
99.8% is the percent of bags contain between 62 and 86 potato chips.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 74
Standard Deviation, σ = 4
We are given that the distribution of number of potato chips in a bag is a bell shaped distribution that is a normal distribution.
Formula:
[tex]z_{score} = \displaystyle\frac{x-\mu}{\sigma}[/tex]
P( bags contain between 62 and 86 potato chips)
[tex]P(62 \leq x \leq 86) = P(\displaystyle\frac{62 - 74}{4} \leq z \leq \displaystyle\frac{86-74}{4}) = P(-3 \leq z \leq 3)\\\\= P(z \leq 3) - P(z < -3)\\= 0.999 - 0.001 = 0.998 = 99.8\%[/tex]
[tex]P(62 \leq x \leq 86) = 99.8\%[/tex]
Answer:
99.7% is the percent of bags contain between 62 and 86 potato chips.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 74
Standard Deviation, σ = 4
We are given that the distribution of number of potato chips in a bag is a bell shaped distribution that is a normal distribution.
Formula:
P( bags contain between 62 and 86 potato chips)
