Dave walked to his friend's house at a rate of 4 mph and returned back biking at a rate of 10 mph. If it took him 18 minutes longer to walk than to bike, what was the total distance of the round trip?

Respuesta :

Answer:

The total distance of the round trip was 4 miles

Step-by-step explanation:

1. Let's check all the information given to answer the question correctly:

Speed of Dave walking to his friend's house = 4 mph

Speed of Dave biking from his friend's house = 10 mph

Time walking is 18 minutes longer than time biking

2. What was the total distance of the round trip?

Time walking = x

Time biking = x - 18

For solving x, we will use the following equation:

4x = 10 * (x - 18)

4x = 10x - 180

-6x = - 180

x = -180/-6 (Dividing by - 6)

x = 30

Dave walked 30 minutes and biked 12 minutes, now we can calculate the total distance, this way:

30 minutes = 0.5 hours and 12 minutes = 0.2 hours

Total distance = 4 * 0.5 + 10 * 0.2

Total distance = 2 + 2

Total distance = 4 miles

The total distance of the round trip can be calculated by creating the system equation as per the given statement.

The total distance is [tex]4 \:\rm mile[/tex].

Given:

The speed of Dave walked to his friend's house is [tex]4 \:\rm mph[/tex].

The speed of Dave returned back biking is [tex]10\:\rm mph[/tex].

As per the given statement he took 18 min longer to walk.

Let the walking time is [tex]x[/tex], and biking time is [tex]x-18[/tex].

As per given statement, write the system equation.

[tex]4x=10\times (x-18)\\-6x=-180\\x=30[/tex]

Thus, the Dave's walked time is [tex]30 \:\rm min[/tex].

Now, Dave's biking time is [tex]x-12=30-12=18\:\rm min[/tex].

Convert the the minute to hour.

[tex]1 \:\rm min=\frac{1}{60}\rm \:min\\30 \:\rm min=\frac{30}{60}\rm \:min\\\\30 \:\rm min=\frac{1}{2} \rm \:hour\\12\:\rm min=\frac{12}{60} \rm \:hour\\12\:\rm min=\frac{1}{5} \rm \:hour[/tex]

Calculate the total distance covered by Dave.

[tex]\:\rm Total\: Distance=4\times\frac{1}{2}+10\times \frac{1}{5}\\\:\rm Total\: Distance=4 \:\rm miles[/tex]

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