Answer:
[tex]\large\boxed{x=2\sqrt{34}}[/tex]
Step-by-step explanation:
The Pythagorean theorem:
[tex]leg^2+leg^2=hypotenuse^2[/tex]
We have
[tex]leg=10,\ leg=6,\ hypotenuse=x[/tex]
Substitute:
[tex]x^2=10^2+6^2\\\\x^2=100+36\\\\x^2=136\to x=\sqrt{136}\\\\x=\sqrt{(4)(34)}\\\\x=\sqrt4\cdot\sqrt{34}\\\\\boxed{x=2\sqrt{34}}[/tex]
