Caitlyn calculated the probability of the complement of rolling a number greater than 2 on a 6-side number cube. She made her calculation as follows. Did she make an error? Explain.

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Answer:

Yes, she made an error because she didn't define the problem correctly.

Step-by-step explanation:

In the picture attached, the complete question is shown.

Let's define

A: rolling a number greater than 2

Complement of an event are all outcomes that are not the event, then the complement of rolling a number greater than 2 is rolling a number less than or equal to 2 (notice that 2 is not greater than 2). The outcomes that satisfied this criteria are {1, 2}, that makes a total of 2 possibilities. In a 6-side number cube there are 6 possible outcomes, then:

p(Complement of A) = 2/6 = 1/3

Ver imagen jbiain

The probability of the complement of rolling a number greater than [tex]2[/tex] on a [tex]6[/tex]-side number cube is [tex]0.333[/tex]. If Caitlyn calculated the probability as 0.33, then she is correct.

Given information:

Caitlyn calculated the probability of the complement of rolling a number greater than [tex]2[/tex] on a [tex]6[/tex]-side number cube.

According to question,

Complement of a number greater than [tex]2[/tex] is "a number not greater than 2".

Now, [tex]P(E)=\frac{\rm{No\;of\;favourable\;outcomes}}{\rm{Total\; number\;of \;outcomes}}[/tex]

Then, [tex]P(\rm{number \; not \; greater \;than \;2})=\frac{2}{6} =\frac{1}{3}[/tex]

Therefore, the probability of the complement of rolling a number greater than [tex]2[/tex] on a [tex]6[/tex]-side number cube is [tex]0.333[/tex].

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