Answer:
14
Step-by-step explanation:
We are given that
Sum of two digit numbers=123422
The two digits numbers are ABC10+ABC12.
Let five digit number of the form =10000A+1000B+100C+10D+E
According to question
[tex]10000A+1000B+100C+10+0+10000A+1000B+100C+10+2=123422[/tex]
[tex]20000A+2000B+200C+20+2=120000+3000+400+20+2[/tex]
Comparing on both sides
C+C should be 14 to obtained 4.Then, carries 1
2C=14
[tex]C=\frac{14}{2}=7[/tex]
2B+1 =3
B+B should not give anything carry as that it will make A to satisfy the addition.
2B=3-1=2
[tex]B=\frac{2}{2}=1[/tex]
2A=12
[tex]A=\frac{12}{2}=6[/tex]
Therefore, the five digit numbers are 61710 and 61712
Sum =61710+61712=123422
A+B+C=6+1+7=14
Hence , A+B+C=14
