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HELP!! BRAINLIEST 50 POINTS

2 LiOH + CO2 = Li2CO3 + H2O
(it doesn’t have to be this equation, just any balanced double replacement one)

For the above equation, demonstrate that it obeys the law of conservation of mass. Calculate the mass of reactants and products to show they are equal. Show all work

Respuesta :

Neetoo

Answer:

The given equation obey the law of conservation of mass.

Explanation:

Chemical equation:

2LiOH + CO₂  →   Li₂CO₃ + H₂O

There are equal number of atoms of oxygen, hydrogen and lithium on both side of equation so it obey the law of conservation of mass.

Law of conservation of mass:

According to the law of conservation mass, mass can neither be created nor destroyed in a chemical equation.

2LiOH                +            CO₂         →         Li₂CO₃           +                    H₂O

2(6.941 + 16 + 1)  +          12+32                   6.941×2 + 12 + 3×16     +       18

47.882 + 44                                                  13.882 +12+48   +   18

91.882 g                                                                91.882 g

The mass of reactants and product are equal.

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