The standard form of the equation of the circle with its center at (-2,0), and a radius of 10 is [tex](x+2)^{2}+y^{2}=100[/tex]
We have been given the center of a circle and radius which are (-2,0) and 10 respectively
To find: Standard form of the equation of the circle
The standard form for the equation of a circle is given as:
[tex](x-a)^{2}+(y-b)^{2}=r^{2}[/tex]
Where (a, b) are the coordinate of the centre of circle and r is the radius
Now on substituting values we get,
[tex]\begin{array}{l}{(x-(-2))^{2}+(y-0)^{2}=10^{2}} \\\\ {(x+2)^{2}+y^{2}=100} \\\\ {(x+2)^{2}+y^{2}=100}\end{array}[/tex]
So, the required standard equation of circle is :-
[tex](x+2)^{2}+y^{2}=100[/tex]
