Answer:
A
Step-by-step explanation:
Using the rules of exponents
[tex]a^{m}[/tex] × [tex]a^{n}[/tex] ⇔ [tex]a^{(m+n)}[/tex]
[tex]a^{-m}[/tex] = [tex]\frac{1}{a^{m} }[/tex]
Given
[tex]3^{\frac{2}{5} }[/tex] × [tex]3^{-\frac{7}{5} }[/tex]
= [tex]3^{\frac{2}{5}-\frac{7}{5} }[/tex]
= [tex]3^{-\frac{5}{5} }[/tex]
= [tex]3^{-1}[/tex]
= [tex]\frac{1}{3}[/tex] → A
