Answer:
Option C.
Step-by-step explanation:
Assume that the below figure attached with this question.
Distance formula:
[tex]Distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
From the below figure it is clear that the vertices of triangle are A(-1,6), B(-1,1) and C(2,2).
Using distance formula we get
[tex]AB=\sqrt{\left(-1-\left(-1\right)\right)^2+\left(1-6\right)^2}\Rightarrow \sqrt{0+25}=5[/tex]
Similarly,
[tex]BC=\sqrt{\left(2-\left(-1\right)\right)^2+\left(2-1\right)^2}=\sqrt{10}[/tex]
[tex]AC=\sqrt{\left(2-\left(-1\right)\right)^2+\left(2-6\right)^2}=5[/tex]
The perimeter of △ABC is
[tex]perimeter=AB+BC+AC[/tex]
[tex]perimeter=5+\sqrt{10}+5[/tex]
[tex]perimeter=10+\sqrt{10}[/tex]
The perimeter of △ABC is [tex]10+\sqrt{10}[/tex].
Therefore, the correct option is C.
Answer:
It is definitely B
Step-by-step explanation:
[tex]10 + \sqrt{10} units[/tex]
