Answer:
Cyclist A
Step-by-step explanation:
given,
velocity of Bicyclist A = 17 mil/hr
acceleration = 32 miles/hr²
velocity of Bicyclist B = 20 miles/hr
acceleration = 2 miles/hr²
which cyclist in front after = 15 minutes = 1/4 hour
using equation of motion for cyclist A
[tex]s = ut +\dfrac{1}{2}at^2[/tex]
[tex]s = 17 \times \dfrac{1}{4} +\dfrac{1}{2}\times 32 \times 0.25^2[/tex]
s = 5.25 mile
using equation of motion for cyclist B
[tex]s = ut +\dfrac{1}{2}at^2[/tex]
[tex]s = 20\times \dfrac{1}{4} +\dfrac{1}{2}\times 2 \times 0.25^2[/tex]
s = 5.0625 mile
Cyclist A will be in-front after 15 minutes
