Answer:
Â
A. 1/6
Explanation:
A male fly trisomic for chromosome 4 with genotype +/+/ey is crossed with a normal, diploid eyeless female. i.e
δ  +/+/ey                                 ey/ey ⊕
+, +, +/+, ey, +/ey, +/ey         ×             ey/ey
ey/+, Â +/ey, Â +/+/ey, Â ey/ey, Â +/ey/ey, Â +/ey/ey
ey/+, Â +/ey, Â +/+/ey, Â ey/ey, Â +/ey/ey, Â +/ey/ey
=2/12
=1/6