Answer:
1.1289 grams ( approx )
Step-by-step explanation:
Since, the final quantity of an element which has half life of n periods,
[tex]A=P(\frac{1}{2})^{\frac{t}{n}}[/tex]
Where,
P = initial quantity,
t = total number of periods,
Here, A = 1 gram, t = 1000 years, n = 5715 years,
By substituting the values,
[tex]1 = P(\frac{1}{2})^\frac{1000}{5715}[/tex]
[tex]\implies P = 2^\frac{1000}{5715}\approx 1.1289[/tex] ( using calculator )
Hence, the initial quantity would be 1.1289 grams ( approx )
