Answer:
28°
Step-by-step explanation:
Recall that the diagonals of a rhombus intersect at 90°
If we let the center of rhombus (where the diagonals intersect) be O,
then ∠AOB = 90°
because all interior angles of a triangle sum to 180°,
∠AOB + ∠OAB + ∠ABO = 180°
90 + (x+6) + 2x = 180 (subtract 90 from both sides)
(x+6) + 2x = 90
3x + 6 = 90 (subtract 6 from both sides)
3x = 84
x = 84/3 = 28°
