contestada

3. What average net force is required to stop a 7 kg shopping cart in 2 s if it's initially
traveling at 3.5 m/s?

Respuesta :

Answer:

The force required to stop the shopping cart is, F = 12.25 N

Explanation:

Given data,

The mass of the shopping cart, m = 7 kg

The initial velocity of the shopping cart, u = 3.5 m/s

The final velocity of the shopping cart, v = 0 m/s

The time period of acceleration, t = 2 s

The change in momentum of the cart,

                                       p = m(u - v)

                                          = 7 (3.5 - 0)

                                          = 24.5 kg m/s

The force is defined as the rate of change of momentum. To stop the shopping cart, the force required is given by the formula

                                            F = p / t

                                                = 24.5 / 2

                                                = 12.25 N

Hence, the force required to stop the shopping cart is, F = 12.25 N

The required net force will be "12.25 N".

According to the question,

  • Mass, m = 7 kg
  • Initial velocity, u = 3.5 m/s
  • Final velocity, v = 0 m/s
  • Time period, t = 2 seconds

Now,

The change in momentum will be:

→ [tex]p = m(u-v)[/tex]

By putting the values, we get

     [tex]= 7(3.5-0)[/tex]

     [tex]= 24.5 \ kg.m/s[/tex]

hence,

The required force will be:

→ [tex]F = \frac{p}{t }[/tex]

      [tex]= \frac{24.5}{2}[/tex]

      [tex]= 12.25 \ N[/tex]

Thus the response above is right.

Learn more about net force here:

https://brainly.com/question/18109210

Q&A Education