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If a normal distribution has a mean of 104 and a standard deviation of 6, what
is the z-score for a value of 116?

Respuesta :

Answer:  2

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Explanation:

The greek letters mu and sigma represent the population mean and population standard deviation respectively.

mu = 104

sigma = 6

x = 116 is the raw score we want to convert to a z score

z = z score

z = (x-mu)/(sigma)

z = (116-104)/(6)

z = 12/6

z = 2

The positive z score tells us the raw score is above the mean.

The z-score for a value of 116 will be 2.

What is the z-score?

The z-score is a statistical evaluation of a value's correlation to the mean of a collection of values, expressed in terms of standard deviation.

The z-score is given as

z = (x – μ) / σ

Where μ is the mean, σ is the standard deviation, and x is the sample.

If a normal distribution has a mean of 104 and a standard deviation of 6.

Then the z-score for a value of 116 will be

z = (116 – 104) / 6

z = 12 / 6

z = 2

More about the z-score link is given below.

https://brainly.com/question/15016913

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