The possible error made by Beth is directly multiplying scale of 5 to area of original triangle and getting area of enlarged triangle, which is wrong.
Step-by-step explanation:
Originally Triangle has height =3.5cm and width=4cm
Beth enlarged the same triangle by scale of 5 and calculate area of triangle
The area of triangle as given as A= [tex]\frac{1}{2} \texrm{ (base) (height)}[/tex]
Area of original triangle is A =[tex]\frac{1}{2}(3.5 \times 4) [/tex]
Since, The triangle is enlarged by scale of 5
New height =3.5x5 = cm and new width=4x5cm
Area of new triangle is
A' = [tex]\frac{1}{2} (\textrm{new width} ) ( \textrm{new height})[/tex]
A' = [tex]\frac{1}{2}(3.5 \times 5)(4\times 5)[/tex]
A' = [tex]\frac{1}{2}(3.5 \times 4)(5^{2})[/tex]
A' = [tex]A (5^{2})[/tex]
Now, Looking what error beth made is:
Beth found Area of new triangle is A' = [tex]\frac{1}{2}(3.5)(4)(5)[/tex]
The possible error made by Beth is directly multiplying scale of 5 to area of original triangle and getting area of enlarged triangle, which is wrong.
