Respuesta :
Answer:
minimum required width of the basin is 42.87 m
Explanation:
given data
diameter particles = 10.0 µm
water temperature = 20 °C
particle density = 1.2 g/mL = 1200 kg/m³
plant treats water = 0.100 m³ /s
deep = 3.5 m
length to width ratio = 5:1
to find out
What is the minimum required width of the basin
solution
we know dynamic viscosity of water = 1.002 ×[tex]10^{-3}[/tex] kg/m-s
and density of water is = 1000 kg/m³
now we apply here stock law for settling velocity that is express as
settling velocity = [tex]\frac{(\rho_p - \rho_w)* gD^2}{18* \mu}[/tex] ..................1
here ρ(p) is particle density and ρ(w) is density of water and µ is dynamic viscosity of water
so put here value
settling velocity = [tex]\frac{(1200-1000)* 9.81*(10*10^{-6})^2}{18* 1.002*10^{-3}}[/tex]
settling velocity = 1.088 × [tex]10^{-5}[/tex] m/s
so now we calculate length of basin
we know length to width ratio is 5:1
so length L = 5b
and
minimum width of basin will be
Q = Area × settling velocity
0.1 = L × b × 1.088 × [tex]10^{-5}[/tex]
0.1 = 5b × b × 1.088 × [tex]10^{-5}[/tex]
b = 42.87 m
so minimum required width of the basin is 42.87 m
