Answer:
The 2 in the numerator should be –2
Step-by-step explanation:
we know that
The formula to solve a quadratic equation of the form
[tex]ax^{2} +bx+c=0[/tex]
is equal to
[tex]x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}[/tex]
in this problem we have
[tex]-2x^{2} +5x-3=0[/tex]
so
[tex]a=-2\\b=5\\c=-3[/tex]
substitute in the formula
[tex]x=\frac{-(5)(+/-)\sqrt{5^{2}-4(-2)(-3)}} {2(-2)}[/tex]
[tex]x=\frac{-5(+/-)\sqrt{25-24}} {-4}[/tex]
[tex]x=\frac{-5(+/-)1} {-4}[/tex]
[tex]x=\frac{-5(+)1} {-4}=1[/tex]
[tex]x=\frac{-5(-)1} {-4}=1.5[/tex]
therefore
The 2 in the numerator should be –2
