Answer:
5.3 g
Explanation:
Data Given:
Sodium acetate CH₃COONa = 13.5 g
Amount of oxygen = ?
Solution:
Molecular weight calculation:
CH₃COONa = 12 + 1 x 3 + 12 + 16 x 2 + 23
CH₃COONa = 82 g/mol
Mass contributed by oxygen = 32 g
calculate the mole percent composition of oxygen in sodium acetate
Since the percentage of compound is 100
So,
Percent of Oxygen = 32 / 82 x 100
Percent of Oxygen = 39 %
it means that for ever gram of sodium acetate there is 0.39 g of oxygen is present.
So, for 13.5 g the mass of Oxygen well be
mass of Oxygen = 0.39 x 13.5
mass of Oxygen = 5.3 g
