Answer:
C) The probability of drawing two blue marbles without replacement  is [tex] \frac{14}{95}[/tex]
Step-by-step explanation:
Total number of blue marbles  = 8
Total marbles = Number  of ( Blue + Red + Green) marbles
            = 8+ 6 + 6 = 20 marbles
Now,Let  E: Event of picking a blue marble
Also, we know that P (any Event E) = [tex]\frac{\textrm{Number of favorable outcomes}}{\textrm{ Total number of outcomes }}[/tex]
⇒ P( Picking first Blue marble) = [tex]\frac{\textrm{Number of blue marbles}}{\textrm{ Total number of marbles }}  = \frac{8}{20}[/tex]
Now, again P( Picking second Blue marble) = [tex]\frac{\textrm{Number of blue marbles left}}{\textrm{ Total number of marbles left }} Â = \frac{7}{19}[/tex]
Again , P( Drawing two blue marbles without replacement)
= P( Picking first Blue marble) Â x P( Picking second Blue marble)
[tex]= \frac{8}{20} Â \times \frac{7}{19} Â = \frac{14}{95}[/tex]
Hence, the probability of drawing two blue marbles without replacement from the bag is [tex] \frac{14}{95}[/tex]
