The distance between the two charges is [tex]0.3 m[/tex]
Explanation:
The electrostatic force between two charged objects is given by Coulomb's law:
[tex]F=k\frac{q_1 q_2}{r^2}[/tex]
where:
[tex]k=8.99\cdot 10^9 Nm^{-2}C^{-2}[/tex] is the Coulomb's constant
[tex]q_1, q_2[/tex] are the charges of the two objects
r is the separation between the two charges
In this problem, we are given the following:
[tex]q_1 = 8\cdot 10^{-5} C[/tex]
[tex]q_2 = 3\cdot 10^{-5} C[/tex]
[tex]F=2.4\cdot 10^2 N[/tex]
Therefore, we can rearrange the equation to solve for r, the distance between the two charges:
[tex]r=\sqrt{\frac{kq_1 q_2}{F}}=\sqrt{\frac{(8.99\cdot 10^9)(8\cdot 10^{-5})(3\cdot 10^{-5})}{2.4\cdot 10^2}}=0.3 m[/tex]
Learn more about electrostatic force:
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