the gcf of two numbers is 170. neither number is divisible by the other. what is the smallest these two numbers could be? (prime factorization of 170 = 2 x x 5 x 17)


please help!!

Respuesta :

aachen

Answer:

[tex]340[/tex]

Step-by-step explanation:

Given: GCF of two numbers is [tex]170[/tex]. neither number is divisible by the other.

To Find: smallest of these two number.

Solution:

As GCF of two numbers is [tex]170[/tex], both number are divisible by [tex]170[/tex].

Prime factor of [tex]170[/tex] [tex]=2\times5\times17[/tex]

multiples of [tex]170[/tex] are [tex]1\times2\times5\times17=170[/tex]

                                           [tex]2\times2\times5\times17=340[/tex]

                                           [tex]3\times2\times5\times17=510[/tex]

GCF of all three multiples is [tex]170[/tex],

Here [tex]340[/tex] and [tex]510[/tex] are the two multiples whose GCF is [tex]170[/tex] and neither is divisible by other

Hence the smallest of two is [tex]340[/tex], the answer is [tex]340[/tex]

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