The increase in potential energy is [tex]5.95\cdot 10^4 J[/tex]
Explanation:
The gravitational potential energy gained by an object lifted above the ground is given by:
[tex]\Delta PE = mg \Delta h[/tex]
where
m is the mass of the object
g is the acceleration of gravity
[tex]\Delta h[/tex] is the change in height of the object
For the beam in this problem, we have
m = 330 kg
[tex]g=9.8 m/s^2[/tex]
[tex]\Delta h = 18.4 m[/tex]
Substituting, we find its gain in potential energy:
[tex]\Delta PE=(330)(9.8)(18.4)=5.95\cdot 10^4 J[/tex]
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