Answer:
The given linear equations has No solution.
Step-by-step explanation:
Given:
[tex]y = 3x-9[/tex]
[tex]x-\frac{1}{3} y= -3[/tex]
Now we have been given 2 linear equation and we need to solve it by substitution method.
[tex]y = 3x-9 \ \ \ \ equation \ 1[/tex]
[tex]x-\frac{1}{3} y= -3 \ \ \ \ equation \ 2[/tex]
Now Substituting the value of equation 1 in equation 2 we get,
[tex]x-\frac{1}{3} (3x-9)= -3\\\\x-\frac{1}{3}\times 3x+ \frac{1}{3}\times 9= -3\\\\x-x+3=-3\\3=-3[/tex]
It can't be true.
Since there is no answer to the equation. It is impossible for the equation to be true no matter what value we assign to the variable.
Hence the above linear equations has No solution.
