The final velocity of the meteor is 4800 m/s
Explanation:
We can solve the problem by applying the impulse theorem, which states that the impulse (the product of force and time interval) exerted on an object is equal to the change in momentum of the object. Mathematically:
[tex]F\Delta t =\Delta p= m(v-u)[/tex]
where
F is the force
[tex]\Delta t[/tex] is the time interval
m is the mass
v is the final velocity
u is the initial velocity
For the meteor in this problem, we have:
F = 40,000 N is the force applied on it
[tex]\Delta t = 0.3 s[/tex] is the time interval during which the force is applied
m = 2.5 kg is the mass of the meteor
u = 0 is the initial velocity
Solving for v, we find the final velocity of the meteor:
[tex]v=u+\frac{F\Delta t}{m}=0+\frac{(40,000)(0.3)}{2.5}=4,800 m/s[/tex]
Learn more about impulse and change in momentum:
brainly.com/question/9484203
#LearnwithBrainly
