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A boy rows a rowboat across a river. The boat moves at 4.3 m/s at a direction of 25°
south of east. Find the east and south components of the rowboats velocity.

Respuesta :

East component: 3.9 m/s

South component: 1.8 m/s

Explanation:

We have to resolve the velocity vector along the east and south axis.

Taking east as positive x-direction and south as positive y-direction, the components of the velocity are given by:

[tex]v_x = v cos \theta\\v_y = v sin \theta[/tex]

where

v = 4.3 m/s is the magnitude of the velocity

[tex]\theta=25^{\circ}[/tex] is the angle between the direction of the velocity and of the x-axis

Substituting into the equations, we find:

East component:

[tex]v_x = (4.3)(cos 25^{\circ})=3.9 m/s[/tex]

South component:

[tex]v_y = (4.3)(sin 25^{\circ})=1.8 m/s[/tex]

Learn more about vector components:

brainly.com/question/2678571

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