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What is the equation of a line that is perpendicular to the line y=- 1/4 x-1 and passes through the point (3, 7)?

A. y = -4x + 19
B. y = 4x - 5
C y = 4x+
D. y=-4x + 31

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SvetkaChem

Answer:

B. y = 4x - 5

Step-by-step explanation:

Line y = - 1/4 x - 1, has slope = - 1/4.

For perpendicular line slope should be negative reciprocal and = 4.

Slope point form is y - y1 = m(x - x1).

y - 7 = 4 (x - 3)

y - 7 = 4x - 12

y = 4x - 5

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