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For the following hypothetical reaction: 3A + 5B —> 3C. How many moles of C can you produce with 2 moles of A and excess B?

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znk

Answer:

2 mol  

Explanation:

           3A + 5B ⟶ 3C

n/mol:   2

The molar ratio is 3 mol C:3 mol A

[tex]\text{Moles of C} = \text{2 mol A} \times \dfrac{\text{3 mol C}}{\text{3 mol A}} = \textbf{2 mol C}[/tex]

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