Velocity of car after 2mins is 36m/s
Distance travelled after 2mins is 2160m
Explanation:
A car start from rest with acceleration a=0.3 [tex]\frac{m}{s^{2} }[/tex]
Using equation of motion,
Velocity v is given by : [tex]v=u+at[/tex]
Distance d is given by [tex]d=ut+\frac{a}{2}t^{2}[/tex]
Velocity after time t=2mins=120s is
[tex]v=u+at[/tex]
As car start from rest u=0
[tex]v=(0.3)(120)[/tex]
[tex]v=(0.3)(120)[/tex]
[tex]v=36m/s[/tex]
Therefore, Velocity of car after 2mins is 36m/s
Distance travelled after 2mins=120s
[tex]d=ut+\frac{a}{2}t^{2}[/tex]
As car start from rest u=0
[tex]d=0+\frac{0.3}{2}(120)^{2}[/tex]
[tex]d=2160m[/tex]
Therefore, Distance travelled after 2mins is 2160m
