Answer:
7[tex]\sqrt{42}[/tex]
Step-by-step explanation:
The diagonal is the hypotenuse of the right triangle with legs 7[tex]\sqrt{3}[/tex]
Use Pythagoras' identity to solve for the diagonal d
The square on the hypotenuse is equal to the sum of the squares on the other 2 sides, that is
d² = (7[tex]\sqrt{3}[/tex])² + (7[tex]\sqrt{3}[/tex])²
= 147 + 147
= 294 ( take the square root of both sides )
d = [tex]\sqrt{294}[/tex] = 7[tex]\sqrt{42}[/tex] ≈ 45.37 ( to 2 dec. places )
