Answer:
11.698 g of NaCl
Explanation:
The molar concentration (M) of a solution is defined as the moles of solute that are dissolved in a liter of solution.
To calculate the grams of solute needed in the statement, you must first calculate the molar mass of NaCl.
mNaCl = mNa + mCl = 22.99g + 35.45g = 58.49 g / mol
Once the molar mass is obtained, it is known that we want to dissolve 0.200 mol of the solute in 1 L of solution, therefore we proceed to perform the mathematical relationship:
1 mole of NaCl _____ 58.49 g
0.200 mol of NaCl _____ X = 11.698 g of NaCl
Calculation: 0.200 mol x 58.49 g / 1 mol = 11.698 g of NaCl
Therefore, to prepare a liter of 0.200 M NaCl solution, 11.698 g of the solute is needed
