Answer:
The time taken by object to dropped the distance of 1089 feet .
Step-by-step explanation:
Given as :
The distance cover by object to fall = 100 feet
The Time taken by the object to fall = 2.5 seconds
Let the speed of the object = s feet/ sec
Now, Speed = [tex]\dfrac{\textrm Distance}{\textrm Time}[/tex]
or, Speed = [tex]\dfrac{\textrm 100}{\textrm 2.5}[/tex]
∴ Speed = 40 feet per sec
Now, again
Distance cover by object = 1089 feet
∵ Speed of object = 40 feet per sec
Let The Time taken at 40 feet per sec = t sec
So, Time = [tex]\dfrac{\textrm Distance}{\textrm Speed}[/tex]
Or , Time = [tex]\dfrac{\textrm 1089}{\textrm 40}[/tex]
or, t = 27.22 seconds
Hence The time taken by object to dropped the distance of 1089 feet . Answer