A cannon Is fired from the edge of a small clip the height of the clear is 80.0 at the cannonball inspired with a perfectly horizontal velocity of 80.0 M/S how far will the cannonball fly horizontally before it strikes the ground

Respuesta :

Answer:it’s 320

Explanation:

The horizontal distance traveled by the cannon before its strikes the ground is 323.2 m.

The given parameters;

height of the cliff, h = 80 m

initial horizontal velocity of the cannon, = 80 m/s

The time of flight of the cannon is calculated as;

[tex]h = v_o_yt + \frac{1}{2} gt^2\\\\80 = 0 + 0.5\times 9.8t^2\\\\80 = 4.9t^2\\\\t^2 = \frac{80}{4.9} \\\\t^2 = 16.326\\\\t = \sqrt{16.326} \\\\t = 4.04 \ s[/tex]

The horizontal distance traveled by the cannon before its strikes the ground is calculated as;

[tex]X = V_0_x \times t\\\\X = 80 \times 4.04\\\\X = 323.2 \ m[/tex]

Thus, the horizontal distance traveled by the cannon before its strikes the ground is 323.2 m.

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