Find the derivative.
Answer:
y prime = [tex]\frac{2x}{ln(x)} -\frac{x}{(ln(x))^2}[/tex]
Step-by-step explanation:
y = x^2 / ln(x)
Rewrite equation
y = x^2 * (ln(x))^-1
Use product and chain rule
y prime = 2x(lnx)^-1 + (x^2)(-1(lnx)^-2*(1/x)
Simplify
y prime = [tex]\frac{2x}{ln(x)} -\frac{x}{(ln(x))^2}[/tex]