The maximum speed of the car is 24.3 m/s
Explanation:
For a car moving along an unbanked turn, the frictional force provides the centripetal force required to keep the car in circular motion. Therefore, we can write:
[tex]\mu mg = m\frac{v^2}{r}[/tex]
where the term on the left is the frictional force while the term on the right is the centripetal force, and where
[tex]\mu=0.40[/tex] is the coefficient of friction between the tires and the road
m is the mass of the car
[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity
v is the speed of the car
r = 150 m is the radius of the curve
Solving for v, we find the (maximum) speed at which the car can move along the turn:
[tex]v=\sqrt{\mu gr}=\sqrt{(0.40)(9.8)(150)}=24.3 m/s[/tex]
For speed larger than this value, the frictional force is no longer enough to keep the car along the turn.
Learn more about circular motion:
brainly.com/question/2562955
brainly.com/question/6372960
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