The specific heat capacity of concrete is [tex]3.0 J/(g^{\circ}C)[/tex]
Explanation:
When a certain amount of energy Q is supplied/given off to/from a sample of substance with mass m, the temperature of the substance increases/decreases by an amount [tex]\Delta T[/tex], according to the equation
[tex]Q=mC_s \Delta T[/tex]
where
m is the mass of the substance
[tex]C_s[/tex] is the specific heat capacity of the substance
[tex]\Delta T[/tex] is the change in temperature of the substance
In this problem, we have:
m = 1 kg = 1000 g is the mass of the concrete slab
[tex]Q = -12,000 J[/tex] is the amount of energy lost by the slab
[tex]\Delta T = 30-26= -4^{\circ}C[/tex] is the change in temperature of the slab
Solving the equation for [tex]C_s[/tex], we find the specific heat capacity of concrete:
[tex]C_s = \frac{Q}{m \Delta T}=\frac{-12,000}{(1000)(-4)}=3.0 J/(g^{\circ}C)[/tex]
Learn more about specific heat capacity:
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