Answer:
D. Sam = c+Y Becca = c+c
Explanation:
Colorblindness is a X-linked trait. Since Sam is a male and not colorblind, there's only one possible genotype he could have which is:
[tex]Sam:\ X^{c+}Y[/tex]
Being c+ the dominant allele for not being colorblind while c is the recessive allele associated with colorblindness.
As for Becca, in order for her to not have colorblindness but her son do, she needs to have a heterozygous genotype and pass down the recessive Y allele to her son. Becca's genotype is:
[tex]Becca:\ X^{c+}X^{c}[/tex]
Therefore, the answer is D. Sam = c+Y Becca = c+c