Answer:
Explanation:
Distance between two slits d = .038 x 10⁻³m
Distance of screen L = 1.6 m
Wave-length of light λ = 4750 x 10⁻¹⁰ m
If x₁ be the position of first bright fringe on the screen
Sinθ₁ = x₁ / L
For position of second bright fringe
Sinθ₂ = x₂ / L
Again, for the formation of first bright fringe
a ) path difference = λ
x₁ d / L = λ
d Sinθ₁ = λ
Sinθ₁ = λ / d
b ) Similarly for second bright fringe
Sinθ₂ = 2 λ / d
c ) Distance between two bright fringes
x₂ - x₁ = y
y = L ( Sinθ₂ - Sinθ₁ )
d )
y = L ( Sinθ₂ - Sinθ₁ )
= L ( 2 λ / d - λ / d )
= Lλ / d
= [tex]\frac{1.6\times4750\times10^{-10}}{.038\times10^{-3}}[/tex]
= 2 x 10⁻² m
= 2 cm .
